Question

A particle moves along the curve $\frac{x^2}{16}+\frac{y^2}{4}=1$. When the rate of change of abscissa is 4 times that of its ordinate, then the quadrant in which the particle lies is

• A. III or IV
• B. I or III
• C. II or III
• D. II or IV

Answer 1

Answer: (D)

II or IV

Answer 2

The correct answer is (D) : II or IV.