Question

A particle is vibrating in SHM with an amplitude of 4 cm. At what displacement from the equilibrium position is its energy half potential and half kinetic?

• A. 1 cm
• B. √2 cm
• C. 2 cm
• D. 2√2 cm

Answer 1

Answer: (D)

2√2 cm

Answer 2

According to the question given

$\frac{1}{2}m\omega^{2}y^{2} = \frac{1}{2}\omega^{2}\left( a^{2} - y^{2} \right)$

or 2y² = a²

or y = $\frac{a}{\sqrt{2}}$ = 2$2\sqrt{2}$cm