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Question

Physics Question on Motion in a straight line

A particle is travelling along a straight line OXOX. The distance xx (in metres) of the particle from OO at a time tt is given by X=37+27tt3X=37+27t-t^{3} where tt is time in seconds. The distance of the particle from OO when it comes to rest is

A

81 m

B

91 m

C

101 m

D

111 m

Answer

91 m

Explanation

Solution

Given, x=37+27tt3x=37 +27 t-t^{3}
v=dxdt=273t2v=\frac{d x}{d t}=27-3 t^{2}
According to problem,
v=0273t2=0v=0 \Rightarrow 27-3 t^{2}=0
Here, t=3st=3 s
x=37+27×3(3)2=91mx=37+27 \times 3-(3)^{2}=91\, m