Question
Physics Question on Motion in a Straight Line
A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it (g = 10 m/s^2 )
A
8m
B
20m
C
10m
D
16m
Answer
10m
Explanation
Solution
The correct option is(C): 10m v^2=u^2-2gs=(10)^2-2gh/2=u^2-gh....(1) 0=u^2-2gh=u^2=2gh putting values of u^2 in(1) 100=2gH-gH=gH H=100/g=100/10= 10 m.