Question

A particle is subjected to two simple harmonic motions along the x and y axes, described by x(t) = $\alpha$sin(2$\omega$t + π) and y(t) = 2$\alpha$ sin($\omega$t). The resultant motion is given by

• A. $\frac{x^2}{\alpha^2}+\frac{y^2}{4\alpha^2}=1$
• B. x2+y2=1
• C. $y^2=x^2(1-\frac{x^2}{4\alpha^2})$
• D. $x^2=y^2(1-\frac{y^2}{4\alpha^2})$

Answer 1

Answer: (D)

$x^2=y^2(1-\frac{y^2}{4\alpha^2})$

Answer 2

The correct answer is (D) : $y^2=x^2(1-\frac{x^2}{4\alpha^2})$