Question
Physics Question on Motion in a plane
A particle is projected with a velocity v such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)
cos25∘ to cos50∘
3g2v2
5g4v2
2gv2
5g4v2
Solution
Given, Range, R=2H But R=4Hcotθ ⇒cotθ=21 From triangle we can say that, sinθ=52 and cosθ=51 So, the range of the projectile R=g2v2sinθcosθ=g2v2×52×51 =5g4v2
A projectile is anything or everything launched into space on which only gravity acts. The sole fundamental operating force on a projectile is gravity. It nevertheless experiences other forces, only to a far lesser extent than gravity, which does not imply that they do not affect it. A projectile's trajectory is the path it takes while travelling. An example of a projectile is a batted or tossed tennis ball.
Generally speaking, there are three different sorts of projectiles:
a projectile that is allowed to fall freely from a significant height.
Straight-up projectile that is launched.
at an angle to the horizontal, launch upward.
A particle that is flung obliquely towards the earth's surface travels along a curved route with constant acceleration that is pointed in the direction of the planet's centre. Such a particle's motion is referred to as projectile motion, and its route is known as a projectile.
In Projectile Motion, there are two separate, concurrent rectilinear motions:
Along the x-axis: Uniform Velocity which is repsonsible for the horizontal (forward) motion of the particle.
Along the y-axis: Uniform Acceleration which is repsonsible for the vertical (downward) motion of the particle.
Acceleration of a particle in horizontal and vertical projectile motion is:
Gravitational acceleration (g) moves downward and vertically.
There is no acceleration of the bullet in its horizontal path, as evidenced by the projectile's steady horizontal velocity.