Question
Question: A particle is projected with a velocity \(u\) in horizontal direction as shown in the figure. find \...
A particle is projected with a velocity u in horizontal direction as shown in the figure. find u(approx.) so that the particle collides orthogonally with the inclined plane of the fixed wedge.
A) 10m/s
B) 20m/s
C) 102m/s
D) None of these
Solution
In order to solve this question you have to break the velocity components of the moving particle and write the force equation and then apply the equilibrium condition. You should remember all the concepts related to wedges. Also, keep in mind that in this question the particle’s velocity component parallel to the inclined plane should be zero.
Complete step by step solution:
Considering plane along the wedge axis,
As we know that when a particle collides with the plane, its velocity component which is parallel to the inclined plane should be zero.
⇒ucosθ−gsinθ×t=0
On further solving, we have
⇒t=gtanθu
And also from the same equation, we get the value of u as
⇒u=gt×tanθ
On putting θ=30∘ in the above equation, we have
⇒u=3gt …….(1)
Now, consider the plane along with the x-y axis, we have
Horizontal displacement before the particle hits the plane =ut
And, the vertical displacement during the t time =21gt2
Now, tan30∘=uth−21gt2
⇒31=uth−21gt2
On solving the above equation for t, we have
⇒t=5g6h
On putting the given values h=55m and g=9.8m/s2 we get
⇒t=2.5938sec
Now, putting that above value of time in the equation (1), we have
⇒u=39.8×2.5938
On further solving this, we get the value of the initial velocity u ,
⇒u=14.69≃102m/s
Therefore, the correct option is (C).
Note: Always keep in mind that if the wedge is at rest then the problem should be solved by the normal way in which we write the force equations and applying the equilibrium conditions and if the wedge is in accelerating motion then everything will be converted into a wedge frame of reference and then solve the question by applying pseudo force.