Question: A particle is projected with a velocity $6\widehat{i} + 8\widehat{j}$, 2m away from a vertical wal...

Question

A particle is projected with a velocity $6\widehat{i} + 8\widehat{j}$ , 2m away from a vertical wall. After striking the wall it lands at …………… away from the wall B

Answer 1

Solution

T = $\frac{2u_{y}}{a_{y}} = \frac{2 \times 8}{10} = 1.6s$

t = 3/6 = 0.5 s

x = u_x (T - t) = 6(1.6 – 0.5) = 6.6 m

Question: A particle is projected with a velocity \(6\widehat{i} + 8\widehat{j}\), 2m away from a vertical wal...

Solution