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Question

Question: A particle is projected with a speed 10 \(\sqrt{2}\) m/s and at angle 45<sup>0</sup> with the horizo...

A particle is projected with a speed 10 2\sqrt{2} m/s and at angle 450 with the horizontal. The rate of change of speed with respect to time at t = 1 s is (g = 10 m/s2)

A

102\frac{10}{\sqrt{2}} m/s2

B

10 m/s2

C

zero

D

5 m/s2

Answer

zero

Explanation

Solution

At t = 1s, particle is at maximum height.

Angle between velocity vector and acceleration vector is 90º.

Hence at this position rate of change of speed with respect to time is zero.