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Question

Physics Question on Motion in a plane

A Particle is projected vertically upward reaches 136 m height. What will be the maximum range for the particle projected with same speed ?

A

272 m

B

280 m

C

290 m

D

300 m

Answer

272 m

Explanation

Solution

U22g\frac{U2}{2g} =Hmax=136m= Hmax = 136 m

\text{for maximum ranges}$$ R = U2g\frac{U2}{g}

Rmax=2×HmaxRmax= 2 \times Hmax

Rmax=272mRmax = 272 m