Question
Physics Question on Motion in a plane
A Particle is projected vertically upward reaches 136 m height. What will be the maximum range for the particle projected with same speed ?
A
272 m
B
280 m
C
290 m
D
300 m
Answer
272 m
Explanation
Solution
2gU2 =Hmax=136m
\text{for maximum ranges}$$ R = gU2
Rmax=2×Hmax
Rmax=272m