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Question

Physics Question on Motion in a straight line

A particle is moving with constant acceleration from AA to BB in a straight line ABAB. If uu and vv are the velocities at AA and BB respectively then its velocity at the midpoint CC will be

A

(u2+v22u)2{{\left( \frac{{{u}^{2}}+{{v}^{2}}}{2u} \right)}^{2}}

B

u+v2\frac{u+v}{2}

C

vu2\frac{v-u}{2}

D

u2+v22\sqrt{\frac{{{u}^{2}}+{{v}^{2}}}{2}}

Answer

u2+v22\sqrt{\frac{{{u}^{2}}+{{v}^{2}}}{2}}

Explanation

Solution

We have standard result for this type of velocity =u2+v22=\sqrt{\frac{{{u}^{2}}+{{v}^{2}}}{2}}