Question

A particle is moving on a circular path with constant speed v. What is the change in its velocity after it has described an angle of 60º ?

• A. $v\sqrt{2}$
• B. $v\sqrt{3}$
• C. V
• D. 2 v

Answer 1

Answer: (C)

V

Answer 2

2 v sin$\left( \frac{60º}{2} \right)$ = v