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Physics Question on simple harmonic motion

A particle is moving in a straight line with simple harmonic motion of amplitude ‘A’. At a distance B from the mean position, the particle receives a blow in the direction of motion which instantaneously doubles the velocity. The new amplitude A' will be,

A

4A2−3B2\sqrt{4A^2-3B^2}

B

2A

C

3A2−4B2\sqrt{3A^2-4B^2}

D

A

Answer

4A2−3B2\sqrt{4A^2-3B^2}

Explanation

Solution

The correct option is (A): 4A2−3B2\sqrt{4A^2-3B^2}