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Question

Question: A particle is moving in a straight line with constant acceleration \(a\) and initial velocity \({v_0...

A particle is moving in a straight line with constant acceleration aa and initial velocity v0{v_0}. What will be the average velocity during the first tt second?
A) v0+12at{v_0} + \dfrac{1}{2}at
B) v0+at{v_0} + at
C) v0+at2\dfrac{{{v_0} + at}}{2}
D) v02\dfrac{{{v_0}}}{2}

Explanation

Solution

The average velocity of a particle in a time interval tt is the total displacement per unit time. So, first calculate the total displacement in the time interval. The total displacement can be calculated by using the formula s=ut+12at2s = ut + \dfrac{1}{2}a{t^2} where uu is the initial velocity of the particle, aa is its constant acceleration and tt is the time.

Complete step by step answer:
As given in the question that the particle is moving in a straight line with constant acceleration aa and initial velocity v0{v_0} and we have to calculate its average velocity during first tt second.
We know that the average velocity of a particle in a time interval tt is the total displacement per unit time. So, we have to calculate the total displacement in the time interval.
The total displacement can be calculated by using the formula s=ut+12at2s = ut + \dfrac{1}{2}a{t^2} where uu is the initial velocity of the particle, aa is its constant acceleration and tt is the time.
So, according to the question, u=v0u = {v_0}
Therefore, the total displacement of the particle in first tt second is given by
s=v0t+12at2s = {v_0}t + \dfrac{1}{2}a{t^2}
And we know that average velocity is given by vav=Total DisplacementTime taken{v_{av}} = \dfrac{{{\text{Total Displacement}}}}{{{\text{Time taken}}}}
Therefore, the average velocity of the particle in first tt second is given by
vav=st=v0t+12at2t=v0+12at{v_{av}} = \dfrac{s}{t} = \dfrac{{{v_0}t + \dfrac{1}{2}a{t^2}}}{t} = {v_0} + \dfrac{1}{2}at

Hence, option A is correct.

Note: We can apply the formula for displacement s=ut+12at2s = ut + \dfrac{1}{2}a{t^2} only when the acceleration of the particle is constant throughout the time in consideration. This formula can be derived by both analytical and graphical methods. As velocity is a vector quantity it must have a direction. The direction of average velocity is in the direction of the total displacement.