Question

A particle is moving in a circular path of radius a under the action of an attractive potential $U = - \frac{k}{2r^2}$. Its total energy is -

• A. $- \frac{k}{4a^2}$
• B. $\frac{k}{2a^2}$
• C. zero
• D. $- \frac{3}{2} \frac{k}{a^2}$

Answer 1

Answer: (C)

zero

Answer 2

$F=\frac{-d U}{d r} \,\,\,\,\,\left[U=-\frac{k}{2 r^{2}}\right]$
$\frac{m v^{2}}{r}=\frac{k}{r^{3}} \,\,\,\,\,$ [This force provides necessary centripetal force]
$\Rightarrow m v^{2}=\frac{k}{r^{2}}$
$\Rightarrow K . E=\frac{k}{2 r^{2}}$
$\Rightarrow P . E=-\frac{k}{2 r^{2}}$
Total energy $=$ Zero