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Question

Question: A particle is moving in a circular path and its acceleration vector is making an angle of 30° with t...

A particle is moving in a circular path and its acceleration vector is making an angle of 30° with the velocity vector, then the ratio of centripetal acceleration to its tangential acceleration is –

A

12\frac{1}{2}

B

32\frac{\sqrt{3}}{2}

C

13\frac{1}{\sqrt{3}}

D

3\sqrt{3}

Answer

13\frac{1}{\sqrt{3}}

Explanation

Solution

tan q = acat\frac{a_{c}}{a_{t}}

\ acat\frac{a_{c}}{a_{t}} = tan 300 = 13\frac{1}{\sqrt{3}}