Question

A particle is moving along a circular path of radius 2 m and with uniform speed of 5 ms^–1. What will be the change in velocity when the particle completes half of the revolution

• A. Zero
• B. 10 ms^–1
• C. $10\sqrt{2}ms^{- 1}$
• D. $10/\sqrt{2}ms^{- 1}$

Answer 1

Answer: (B)

10 ms^–1

Answer 2

$\Delta v = 2v\sin\left( \frac{\theta}{2} \right) = 2 \times 5\sin\left( \frac{180^{o}}{2} \right)$

$= 2 \times 5\sin 90^{o} = 10m/s$