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Physics Question on Acceleration

A particle is having uniform acceleration. If its displacement from t to (t+1)(t + 1) second is 120120 mm and change in velocity is 50  m/s50 \;m/s. Find its displacement (in m) in (t+2)th(t + 2)^{th} second

Answer

Displacement will be:\text{Displacement will be:}

a=50  m/s2a=50\;m/s^2

120=u+a2(2(t+1)1)120=u+\frac{a}{2}(2(t+1)-1)

u=12025(2t+1)u=120-25(2t+1)

s=u+a2(2(t+2)1)s'=u+\frac{a}{2}(2(t+2)-1)

=u+25(2t+3)=u+25(2t+3)

The Correct Answer is : 170170