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Question

Question: A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz. ...

A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz. The maximum acceleration of the particle is

A

100m/s2100m ⥂ / ⥂ s^{2}

B

100π2m/s2100\pi^{2}m ⥂ / ⥂ s^{2}

C

100m/s2100m ⥂ / ⥂ s^{2}

D

200π2m/s2200\pi^{2}m ⥂ / ⥂ s^{2}

Answer

200π2m/s2200\pi^{2}m ⥂ / ⥂ s^{2}

Explanation

Solution

A2222max=200π2m/s{A{{2^{2}}^{2}}^{2}}_{\max} = 200\pi^{2}m/s