Question

A particle is dropped from a height h. A constant horizontal velocity is given to the particle. Taking g to be constant everywhere, kinetic energy E of the particle with reference to time t is correctly shown in

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

Kinetic energy, E = $\frac { 1 } { 2 }$ mv²

here v² = u² + (gt)²

( vertical component of velocity is gt)

E = $\frac { 1 } { 2 }$m(u² + gt²)

Thus, curve should be a parabola of the type shown by (1)