Question

A particle has velocity √3rg at the highest point in a vertical circle. Find the ratio of tensions at the highest and lowest point.

• A. 1 : 6
• B. 1 : 4
• C. 1 : 3
• D. 1 : 2

Answer 1

Answer: (B)

1 : 4

Answer 2

T_top = $\frac{mv^{2}}{r}$ - mg = 2mg;

$\frac{T_{top}}{T_{bottom}} = \frac{2mg}{2mg + 6mg} = \frac{1}{4}$.