Question

A particle has simple harmonic motion. The equation of its motion is $x = 5\sin\left( 4t - \frac{\pi}{6} \right)$, where x is its displacement. If the displacement of the particle is 3 units, then it velocity is

• A. $\frac{2\pi}{3}$
• B. $\frac{5\pi}{6}$
• C. $20$
• D. $16$

Answer 1

Answer: (D)

$16$

Answer 2

From the given equation, a = 5 and ω = 4

∴ $v = \omega\sqrt{a^{2} - y^{2}} = 4\sqrt{(5)^{2} - (3)^{2}} = 16$