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Question

Physics Question on Motion in a plane

A particle has initial velocity (2i+3j) ( 2 \vec{i} + 3 \vec{j}) and acceleartion (0.3i+0.2j) 0 . 3 \vec{i} + 0 . 2 \vec{j}) The magnitude of velocity after 10 seconds will be

A

9 2\sqrt 2 units

B

5 2\sqrt 2 units

C

5 units

D

9 units

Answer

5 2\sqrt 2 units

Explanation

Solution

v=u+at\vec{ v }=\overrightarrow{ u }+\vec{ a } t
v=(2i^+3j^)+(0.3i^+0.2j^)×10\vec{ v }=(2 \hat{ i }+3 \hat{ j })+(0.3 \hat{ i }+0.2 \hat{ j }) \times 10
v=5i^+5j^\Rightarrow \vec{ v }=5 \hat{ i }+5 \hat{ j }
v=52v =5 \sqrt{2} units