Question

A particle has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. The sum of these displacements is

• A. 12
• B. 10.04 m
• C. 14.31 m
• D. None of these

Answer 1

Answer: (C)

14.31 m

Answer 2

$R = \sqrt{12^{2} + 5^{2} + 6^{2}} ⥂ = ⥂ \sqrt{144 + 25 + 36} ⥂ = ⥂ \sqrt{205} = 14.31\mspace{6mu} m$