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Question

Physics Question on Motion in a plane

A particle has an initial velocity 3i^+4j^3\hat{i}+4\hat{j} and an acceleration of 0.4i^+0.3j^0.4\hat{i}+0.3\hat{j}. Its speed after 10s10\, s is

A

1010 units

B

727\sqrt{2} units

C

77 units

D

8.58.5 units

Answer

727\sqrt{2} units

Explanation

Solution

u=3i^+4j^;a=0.4i^+0.3j^\overrightarrow{u}=3\hat{i}+4\hat{j} ; \overrightarrow{a}=0.4\hat{i}+0.3\hat{j} u=u+at\overrightarrow{u}=\overrightarrow{u}+\overrightarrow{a}t =3i^+4j^+(0.4i^+0.3j^)10=3i^+j^+4i^+3j^=7i^+7j^=3\hat{i}+4\hat{j}+\left(0.4\hat{i}+0.3\hat{j}\right)10=3\hat{i}+\hat{j}+4\hat{i}+3\hat{j}=7\hat{i}+7\hat{j} Speed is 72+72=72\sqrt{7^{2}+7^{2}}=7\sqrt{2} units