Question
Physics Question on Motion in a plane
A particle has an initial velocity 3i^+4j^ and an acceleration of 0.4i^+0.3j^. Its speed after 10s is
A
10 units
B
72 units
C
7 units
D
8.5 units
Answer
72 units
Explanation
Solution
u=3i^+4j^;a=0.4i^+0.3j^ u=u+at =3i^+4j^+(0.4i^+0.3j^)10=3i^+j^+4i^+3j^=7i^+7j^ Speed is 72+72=72 units