Question

A particle has a displacement of $12\,m$ towards east and $5\,m$ towards north and finally $6\,m$ vertically upwards. The sum of these displacement is

• A. 12 m
• B. 10.04 m
• C. 14.31m
• D. None of these

Answer 1

Answer: (C)

14.31m

Answer 2

Resultant $R = S_1 + S_2 + S_3$ $|R|=\sqrt{(12)^2+(5)^2+(6)^2}$ $=\sqrt{144 +25 +36 }=\sqrt{205} \Rightarrow R=14.31 cm$