Question
Physics Question on Motion in a straight line
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 seconds, then
A
s2 = s1
B
s2 = 2s1
C
s2 = 3s1
D
s2 = 4s1
Answer
s2 = 3s1
Explanation
Solution
Let a be the constant acceleration of the particle. Then s=ut+21at2 or s1=0+21×a×(10)2=50a and s2=[0+21a(20)2]−50a=150a ∴s2=3s1