Question

A particle executing simple harmonic motion with an amplitude A and angular frequency$\omega$. The ratio of maximum acceleration to the maximum velocity of the particle is

• A. $\omega$A
• B. $\omega$2A
• C. $\omega$
• D. $\frac{\omega^{2}}{A}$

Answer 1

Answer: (C)

$\omega$

Answer 2

In SHM,

Maximum velocity, $\nu_{\max}$

Maximum acceleration ${a2}_{\max}$

$\therefore\frac{a_{\max}}{v_{\max} = \frac{\omega^{2}A}{\omega A} = \omega}$