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Question: A particle executing simple harmonic motion of amplitude \[5cm\] has a maximum speed of \(31.4cm{s^{...

A particle executing simple harmonic motion of amplitude 5cm5cm has a maximum speed of 31.4cms131.4cm{s^{ - 1}}. The frequency of the oscillation is:
A) 1Hz1Hz
B) 3Hz3Hz
C) 2Hz2Hz
D) 4Hz4Hz

Explanation

Solution

A particle executing simple harmonic motion has several defining quantities associated with it like amplitude, frequency, angular velocity etc. We will use the relations between them to calculate the frequency of oscillation.

Complete step by step solution:
Let’s start by defining amplitude. In simple harmonic motion, the amplitude is the maximum amount of displacement of a particle on the medium from its rest position or the starting point of oscillation. It is denoted by aa.
The maximum speed of oscillation means the maximum linear velocity of the particle with which the particle executes simple harmonic motion. It is denoted by Vmax{V_{\max }}.
The maximum velocity of oscillation is related to the amplitude of oscillation by the following formula,
Vmax=aω{V_{\max }} = a\omega ………. (1)
Where ω\omega is the angular velocity of the particle.
The formula for angular velocity as we know it is,
ω=2πf\omega = 2\pi f ………. (2)
Where ff is the frequency of oscillation.
Frequency of oscillation is defined as the number oscillations per unit time and has the unit of Hertz (Hz)\left( {Hz} \right), or s1{s^{ - 1}}.
Putting the value of ω\omega in equation (1), we get,
Vmax=2πf×a\Rightarrow {V_{\max }} = 2\pi f \times a
f=Vmax2πa\Rightarrow f = \dfrac{{{V_{max}}}}{{2\pi a}}
Substituting the respective values in the above equation we get,
f=31.42×3.14×5=1Hz\therefore f = \dfrac{{31.4}}{{2 \times 3.14 \times 5}} = 1Hz

So our correct answer is option (A).

Additional information:
For a spring with spring constant kk in which a particle is exhibiting SHM with a mass mm, the value of ω\omega becomes ω=km\omega = \sqrt {\dfrac{k}{m}} so the formula for maximum velocity becomes Vmax=Akm{V_{\max }} = A\sqrt {\dfrac{k}{m}} .

Note: After looking at the question, analyse it and apply required relations between the physical quantities. Take care of the system of units. This question was asked in c.g.s. system and the c.g.s unit of frequency is also HzHz. The examiner can also provide the value of angular acceleration, in that case use the relation between angular velocity and acceleration.