Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is:

• A. 2 Hz
• B. 1.5 Hz
• C. 0.5 Hz
• D. 1 Hz

Answer 1

Answer: (D)

1 Hz

Answer 2

Maximum speed of a particle executing SHM is
$u_{max} = a\omega=a(2\pi n)$
$\Rightarrow n = \frac{u_{max}}{2\pi n}$
$u_{max}=31.4 cm/s,a=5\,cm$
Substituting the given values, we have
n = $\frac{31.4}{2\times314\times 5}$ = 1 Hz

Therefore, the correct option is (D): 1 Hz