Question

A particle executing simple harmonic motion of amplitude $5 \,cm$ has maximum speed of $31.4 \,cm/s$. The frequency of its oscillation is

• A. 3 Hz
• B. 2 Hz
• C. 4 Hz
• D. 1 Hz

Answer 1

Answer: (D)

1 Hz

Answer 2

Maximum speed of a particle executing SHM is
$u_{\max } =a \omega=a(2 \pi n)$
$\Rightarrow n =\frac{u_{\max }}{2 \pi a}$
$u_{\max } =31.4 \,cm / s , a=5 \,cm$
Substituting the given values, we have
$n=\frac{31.4}{2 \times 314 \times 5}=1\, Hz$