Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

• A. 3 Hz
• B. 2 Hz
• C. 4 Hz
• D. 1 Hz

Answer 1

Answer: (D)

1 Hz

Answer 2

$v_{\max}$ ⇒ $n = \frac{v_{\max}}{2\pi a\frac{31.4}{2 \times 3.14 \times 5}}$