Question

A particle executing SHM has amplitude $0.01$ and frequency $60\, Hz$. The maximum acceleration of the particle is:

• A. $60\,\pi ^{2}m/s^{2}$
• B. $88\, \pi ^{2}m/s^{2}$
• C. $140\,\pi ^{2}m/s^{2}$
• D. $144\,\pi ^{2}m/s^{2}$

Answer 1

Answer: (D)

$144\,\pi ^{2}m/s^{2}$

Answer 2

Here : Amplitude $a=0.01\, m$ Frequency $f=60\, Hz$ Using the relation for maximum acceleration $=a \omega^{2}=a(2 \pi f)^{2}=a\left(4 \pi^{2} f^{2}\right)$ $=0.01 \times \pi^{2} \times 4 \times(60)^{2}$ $=144\, \pi^{2} m / s ^{2}$