Question

A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is _________s.

Answer 1

$A = 8$ $cm$

$T = 6$ $s$

$A$ $cos\bigg(\frac{2πt}{T}\bigg)=\frac{A}{2}$

$⇒\frac{2πt}{T}=\frac{π}{3}$

or

$t=\frac{T}{6}=1s$