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Question

Physics Question on Oscillations

A particle executes SHM with a period of 8s8\,s and amplitude 4cm4\,cm . Its maximum speed in cm/scm/s, is

A

π\pi

B

π2\frac{\pi }{2}

C

π3\frac{\pi }{3}

D

π4\frac{\pi }{4}

Answer

π\pi

Explanation

Solution

For a particle executing SHM
vmax=Aωv_{\max }=A \omega
=4×2πT=4 \times \frac{2 \pi}{T}
=4×2π8=πcms1=4 \times \frac{2 \pi}{8}=\pi cm s ^{-1}