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Question: A particle executes SHM of amplitude 5cm and period 3s. The velocity of the particle at a distance 4...

A particle executes SHM of amplitude 5cm and period 3s. The velocity of the particle at a distance 4 cm from the mean position-

A

8 cm/s

B

12 cm/s

C

4 cm/s

D

6 cm/s

Answer

6 cm/s

Explanation

Solution

2πTa2−x2=2×3325−16\frac{2\pi}{T}\sqrt{a^{2} - x^{2}} = \frac{2 \times 3}{3}\sqrt{25 - 16}

= 6 cm/s