Question

A particle executes SHM, its time period is $16\, s$. If it passes through the centre of oscillation then its velocity is $2\, ms^{-1}$ at times $2\, s$. The amplitude will be

• A. 7.2 m
• B. 4 cm
• C. 6 cm
• D. 0.72 m

Answer 1

Answer: (A)

7.2 m

Answer 2

$\, \, \, \, \, \, \, \, \, \, \, \, v=a \omega cos \omega t$ $\therefore \, \, \, \, \, \, \, \, \, \, \, 2=a.\frac{2\pi}{16}. cos \frac{2\pi}{16}.2$ $or \, \, \, \, \, \, \, \, \, \, a=\frac{16\sqrt 2}{\pi} =7.2 m$