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Question

Question: A particle executes S.H.M (amplitude = A) between x = – A & x = + A. The time taken for it to go fro...

A particle executes S.H.M (amplitude = A) between x = – A & x = + A. The time taken for it to go from 0 to A/2 is T1& to go from A/2 to A is T2. Then -

A

T1< T2

B

T1> T2

C

T1 = T2

D

T1 = 2T2

Answer

T1< T2

Explanation

Solution

If x = A sin ωt

For x = A/2 ⇒ T1 = π6ω\frac{\pi}{6\omega}

T2 = π3ω\frac{\pi}{3\omega}

i.e. T1 < T2