Question
Question: A particle executes S.H.M (amplitude = A) between x = – A & x = + A. The time taken for it to go fro...
A particle executes S.H.M (amplitude = A) between x = – A & x = + A. The time taken for it to go from 0 to A/2 is T1& to go from A/2 to A is T2. Then -
A
T1< T2
B
T1> T2
C
T1 = T2
D
T1 = 2T2
Answer
T1< T2
Explanation
Solution
If x = A sin ωt
For x = A/2 ⇒ T1 = 6ωπ
T2 = 3ωπ
i.e. T1 < T2