Question

A particle executes SHM along a straight line so that its period is 12s. The time it takes in traversing a distance equal to half its amplitude from its equilibrium position is –

• A. 6s
• B. 4s
• C. 2s
• D. 1s

Answer 1

Answer: (D)

1s

Answer 2

E = a sin wt $\frac { \mathrm { a } } { 2 }$ = a sin wt

or $\frac { 1 } { 2 }$= sin wt

or sin $\frac { \pi } { 6 }$= sin $\frac { 2 \pi } { 12 }$t

t = 1s