Question

A particle executes S.H.M. along x-axis. The force acting on it is given by (A, k>0)

• A. A cos (kx)
• B. A $e^{ - kx}$
• C. Akx
• D. - Akx

Answer 1

Answer: (D)

- Akx

Answer 2

For simple harmonic motion, $\frac{ d^2 x }{ dt^2 } \propto - x$.
Therefore force acting on the particle = - Akx.