Question

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

• A. $\frac {\sqrt 5}{\pi}$
• B. $\frac {\sqrt 5}{2\pi}$
• C. $\frac {4\pi}{\sqrt 5}$
• D. $\frac {2\pi}{\sqrt 3}$

Answer 1

Answer: (C)

$\frac {4\pi}{\sqrt 5}$

Answer 2

The correct option is (C): $\frac {4\pi}{\sqrt 5}$.