Question

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude

• A. T / 2
• B. T / 4
• C. T / 8
• D. T / 12

Answer 1

Answer: (D)

T / 12

Answer 2

$y = A\sin\omega t = \frac{A\sin 2\pi}{T}t$ ⇒ $\frac{A}{2} = A\sin\frac{2\pi t}{T}$⇒ $t = \frac{T}{12}$.