Question

A particle connected with light thread is performing vertical circular motion. Speed at point B (Lowermost point) is sufficient, so that it is able to complete its circular motion. Ignoring air friction, find the ratio of kinetic energy at A to that at B. (A being top-most point)

• A. $1 : 5$
• B. $5 : 1$
• C. $1: 7\sqrt2$
• D. $1: 5\sqrt2$

Answer 1

Answer: (A)

$1 : 5$

Answer 2

The correct option is (A): $1 : 5$