Question
Question: A particle at the end of a spring executes simple harmonic motion with a period t<sub>1</sub>, while...
A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for another spring is t2. If the period of oscillation with the two springs in series is T, then –
A
T = t1 + t2
B
T2 = t12 + t22
C
T–1 = t1–1 + t2t–1
D
T–2 = t1–2 + t2–2
Answer
T2 = t12 + t22
Explanation
Solution
t1 = 2p k2m….(2)
When springs are in series then
T = 2p= 2p
squaring and adding (1) & (2) we get
+
= 4p2
+4p2
= 4p2mor
+
= T2