Question

A partical executes SHM of frequency f. The frequency of its kinetic energy is

• A. f
• B. $\frac { f } { 2 }$
• C. 2f
• D. Zero

Answer 1

Answer: (C)

2f

Answer 2

ke$\frac { 1 } { 2 } m \omega ^ { 2 } \left( x _ { 0 } ^ { 2 } - x ^ { 2 } \right)$

= $\frac { 1 } { 2 } m \omega ^ { 2 } \left( x _ { 0 } ^ { 2 } - x _ { 0 } ^ { 2 } \sin ^ { 2 } \omega \right)$

= $\frac { 1 } { 2 } m \omega ^ { 2 } x _ { 0 } ^ { 2 } \left( \frac { 1 + \cos ^ { 2 } \omega } { 2 } \right)$

Note the frequency is 2ω or 2f