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Physics Question on Magnetism and matter

A paramagnetic substance of susceptibility 3×10−43\times {{10}^{-4}} is placed in a magnetic field of 4×10−4Am−14\times {{10}^{-4}}A{{m}^{-1}} . Then the intensity of .magnetization in the units of Am−1A{{m}^{-1}} is

A

1.33×1081.33\times {{10}^{8}}

B

0.75×10−80.75\times {{10}^{-8}}

C

12×10−812\times {{10}^{-8}}

D

14×10−814\times {{10}^{-8}}

Answer

12×10−812\times {{10}^{-8}}

Explanation

Solution

Susceptibility (χ)(\chi ) =intensity of magnetisation(I)magnetic field(B)=\frac{intensity\text{ }of\text{ }magnetisation(I)}{magnetic\text{ }field(B)}
or I=χBI=\chi B
∴\therefore I=3×10−4×4×10−4I=3\times {{10}^{-4}}\times 4\times {{10}^{-4}}
or I=12×10−8Am−1I=12\times {{10}^{-8}}A{{m}^{-1}}