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Physics Question on Magnetism and matter

A paramagnetic substance in the form of a cube with sides 1 cm1\, cm has a magnetic dipole moment of 20×10−6  J/T20 \times 10^{-6} \; J/T when a magnetic intensity of 60×103  A/m60 \times 10^3 \; A/m is applied. Its magnetic susceptibility is :

A

2.3×10−22.3 \times 10^{-2}

B

3.3×10−23.3 \times 10^{-2}

C

3.3×10−43.3 \times 10^{-4}

D

4.3×10−24.3 \times 10^{-2}

Answer

3.3×10−43.3 \times 10^{-4}

Explanation

Solution

χ=IH\chi = \frac{I}{H}
I=Magnetic  momentVolumeI = \frac{\text{Magnetic} \; \text{moment}}{\text{Volume}}
I=20×10−610−6=20N/m2I = \frac{20 \times10^{-6}}{10^{-6}} = 20 N /m^{2}
χ=2060×10+3=13×10−3\chi = \frac{20}{60 \times10^{+3}} = \frac{1}{3} \times10^{-3}
=0.33×10−3=3.3×10−4= 0.33 \times10^{-3} = 3.3 \times10^{-4}