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Question: A paramagnetic sample shows a net magnetisation of 8 Am’1 when placed in an external magnetic field ...

A paramagnetic sample shows a net magnetisation of 8 Am’1 when placed in an external magnetic field of 0.6 T at a temperature of 4 K. When the same sample is placed in an external magnetic field of 0.2 T at a temperature of 16 K, the magnetisation will be

A

B

C

6 A m-1

D

2.4 A m-1

Answer

Explanation

Solution

Here

M1=8Am1, B1=0.6 T, T1=4k,B2=0.2 T, T2=16 K\mathrm { M } _ { 1 } = 8 \mathrm { Am } ^ { - 1 } , \mathrm {~B} _ { 1 } = 0.6 \mathrm {~T} , \mathrm {~T} _ { 1 } = 4 \mathrm { k } , \mathrm { B } _ { 2 } = 0.2 \mathrm {~T} , \mathrm {~T} _ { 2 } = 16 \mathrm {~K}then, for paramagnetic materials

Magnetization (M) (Curie’s law)

Now, in the first case, M1=CB1 T1\mathrm { M } _ { 1 } = \frac { \mathrm { CB } _ { 1 } } { \mathrm {~T} _ { 1 } } ….. (i)

And in the second case ….. (ii)

Dividing equation (i) by (ii), we get

M2=812=23Am1\mathrm { M } _ { 2 } = \frac { 8 } { 12 } = \frac { 2 } { 3 } \mathrm { Am } ^ { - 1 }