Question
Question: A parallel sided block of a glass of refractive index 1.5 which is 36 mm thick rests on the floor of...
A parallel sided block of a glass of refractive index 1.5 which is 36 mm thick rests on the floor of a tank which is filled with water (refractive index = 4/3). The difference between the apparent depth of the floor at A & B when seen from vertically above is equal to:
A. 2 mm
B. 3 mm
C. 4 mm
D. none of these
Solution
Using the formula for calculating the apparent depth, the calculation should be carried out. The apparent depth of the floors A and B should be calculated using the apparent depth formula. Then, the difference between the apparent depths of the floor should be calculated.
Formula used:
A=μ1t1+μ2t2
Complete step by step answer:
From given, we have the data,
The refractive index of a parallel sided block of glass, μ2=1.5
The thickness of the parallel sided block of glass, t2=36mm
The refractive index of the water filled in the tank, μ1=34
Let the thickness of the tank filled with water be t1=d,
We will make use of the formula for calculating the apparent depth, given by,
A=μ1t1+μ2t2
Where t1,t2 are the thickness of the materials and μ1,μ2 are refractive indexes.
Firstly, compute the apparent depth in the case floor A.
Here the refractive indices are: μ1=4/3,μ2=1.5
So, we have,
A=4/3d+1.536 …… (1)
Secondly, compute the apparent depth in the case floor B.
Here the refractive indices are: μ1=4/3=μ2
So, we have,
B=4/3d+4/336…… (2)
Now subtract the equations (1) and (2) to obtain the value of the difference in the apparent depths.
So, we get,