Question

A parallel plate capacitor with plate area A and plate separation d = 2 m has a capacitance of 4 μF. The new capacitance of the system, if half of the space between them is filled with a dielectric material of dielectric constant K = 3 (as shown in figure), will be :

• A. 2 μF
• B. 32 μF
• C. 6 μF
• D. 8 μF

Answer 1

Answer: (C)

6 μF

Answer 2

The correct option is (C): 6 μF

Explanation:
Equivalent circuit is

Now, $\frac{ε_0A }{d }$ = 4μF
⇒ \frac{12}{8}$$\frac{ε_0A }{d }
= 6μF